1.

Given : H_(2)(g) + (1)/(2) O_(2)(g) = H_(2)O(g) + q_(1) H_(2)(g) + (1)/(2) O_(2)(g) = H_(2)O(l) + q_(2) The enthalpy of vaporisation of water is equal to

Answer»

`q_(1) + q_(2)`
`q_(1) - q_(2)`
`q_(2) - q_(1)`
`q_(1) q_(2)`

Solution :(i) `H_(g) +½ O_(2) (g) rarr H_(2)0(g) + q_(1)`
(ii) `H_(2)(g) + ½ O _(2) (g) rarr H_(2) O (L) + q_ (2)`
SUBTRACT EQ. (ii) from eq. (i).
`H_(2)O(l) rarr H_(2)O(g) + q_(1) - q_(2)`
:. `DELTA H = -(q_(1) - q_(2)) = q_(2) - q_(1)`


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