1.

Given : (i)MnO_(4)^(-)+8H^++5e^(-)toMn^(2+)+4H_2O , E^0=x_1V (ii)MnO_(2)+4H^++2e^(-)toMn^(2+)+2H_2O , E^0=x_2V Find E^(@) for the following reaction : MnO_(4)^(-)+4H^++3e^(-)toMnO^(2)+2H_2O

Answer»

`x_(2)-x_(1)`
`x_(1)-x_(2)`
`(5x_(1)-2x_2)/3`
`(2x_(1)-5x_2)/3`

SOLUTION :`DeltaG_1^@=-5x_1F , " " DeltaG_2^@=-2x_2F`
`DeltaG_3^@=DeltaG_1^@-DeltaG_2^@ , " " DeltaG_3^@=2x_2F-5x_1F`
`therefore X=(5x_1-2x_2)/3`


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