InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Given is the graph between `(PV)/T` and P for 1 gm of oxygen gas at two different temperatures `T_(1) and T_(2)` Fig. Given, density of oxygen `= 1.427 kg m^(-3)`. The value of `(PV)//(T)` at the point A and the relation between `T_(1) and T_(2)` are respectively : A. `0.256 JK^(-1) and T_(1)ltT_(2)`B. `8.314 J mol^(-1)K^(-1) and T_(1)ltT_(2)`C. `0.256 JK^(-1) and T_(1)gtT_(2)`D. `4.28 JK^(-1) and T_(1)ltT_(2)` |
|
Answer» Correct Answer - C `pV =nRt =(m)/(M)RT` where, m=mass of gas and `(m)/(M) =n =number of moles` `rArr (pV)/(T)=nR=constant for all values of P (ideally it is a straight line) `rArr (pV)/(T)=(1g)/(32g)xx8.31J mol^(-1)K^(-1)=0.256 JK^(-1)` Also `T_(1)gtT_(2)` |
|