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Two perifect gases at absolute temperatures `T_(1) and T_(2)` are mixed. The absolute temperature of the mixture is T. there is no loss of energy.If `m_(1) and m_(2)` are masses of molecules and `n_(1) and n_(2)` are number of molecules, thenA. `T=(T_(1)+T_(2))/(2)`B. `T=(n_(1)T_(1)+n_(2)T_(2))/(n_(1)+n_(2))`C. `T=(n_(1)T_(1)+n_(2)T_(2))/(T_(1)+T_(2))`D. None of the above |
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Answer» Correct Answer - B Average KE per molecule of a gas `=(3)/(2)KT` Before mixing two gases, the averge KE of all molecules of 2 gases `=(3)/(2)kn_(1)T_(1)+(3)/(2)kn_(2)T_(2)` after mixing the average KE of both gases `=(3)/(2)k(n_(1)+n_(2))T` where,T is temperature of mixture `therefore` No loss of enegy. `therefore` " " `(3)/(2)k(n_(1)+n_(2))T=(3)/(2)kn_(1)T_(1)+(3)/(2)kn_(2)T_(2)` `T=(n_(1)T_(1)+n_(2)T_(2))/(n_(1)+n_(2))` |
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