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                                    One litre of oxygen at a pressure of 1 atm and two litres of nitrogen at a pressure of 0.5 atm are introduced into a vessel of volume 1 litre. If there is no change in temperature, the final pressure of the mixture of gas (in atm) isA. 1.5B. 2.5C. 2D. 4 | 
                            
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Answer» Correct Answer - C Ideal gas equation is given by `pV=nRT` " "..(i) For oxygen ,`P =1atm,V=1L,n=n_(0)` Therefore,Eq (i) becomes `therefore` " "` 1xx1=nO_(2)RT rArr n_(O_(2))=1/RT` and `0.5xx2=n_(N_(2))RT rArr n_(N_(2))=1/RT` For mixture of gas, `P_(mix)V_(mix)=n_(mix)RT` Here, `n_(mix)=n_(O_(2))+n_(N_(2))` `therefore` " "`(P_(mix)V_(mix))/(RT)=1/RT+1/RT` `rArr P_(mix)V_(mix)=2`  | 
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