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Given length of chord AB = 12 cm.Distance of chord from center = 8 cm.OC=8 cm .AC= 212 =6 cmIn △OACOA 2 =AC 2 +OC 2OA 2 =(6) 2 +(8) 2 =36+64[ OA=10 cm].∴ Diameter of circle is 2(OA) = 20 cm. |
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Answer» Answer: difficult difficult question sorry really sorry Step-by-step explanation: when I get TIME I will solve it |
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