1.

Given magnetic field equation is vec(B)=3xx10^(-8) sin[omega t-kx + phi] hat(j) then appropriate equation for electric field (vec(E )) will be …….

Answer»

`3xx10^(-9)sin (omega t-kx + phi)hat(K)`
`9 sin (omega t - kx + phi)hat(k)`
`16xx10^(-9)sin (omega t-kx+phi)hat(k)`
`20xx10^(-9)sin(omega t-kx + phi)hat(k)`

Solution :We KNOW that `(|VEC(E )_(0)|)/(|vec(B)_(0)|)=c`
`THEREFORE (E_(0))/(B_(0))=c`
`therefore E_(0)=B_(0)c`
`therefore E_(0)=3xx10^(-8)xx3xx10^(8) ""` [`therefore` From given equation `B_(0)=3xx10^(-8)T`]
`therefore E_(0)=9N//C`
`therefore` Equation of electric field,
`vec(E )=E_(0)sin[omega t-kx + phi)hat(k)`
`therefore vec(E ) = 9 sin [omega t-kx+phi)hat(k)`
Electric field will be in z - DIRECTION.


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