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Given mass number of gold `= 197`, Density of gold `= 19.7 g cm^(-1)`. The radious of the gold atom is appoximately:A. `1.5 xx 10^(-8) m`B. `1.5 xx 10^(-9) m`C. `1.5 xx 10^(-10) m`D. `1.5 xx 10^(-12) m` |
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Answer» Correct Answer - C Volume occupied by one mole of gold `= (197 g)/(19.7 km ^(-3)) = 10 c m ^(3)` Valume of one atom ` = (10)/(6 xx 10^(-23)) = (5)/(3) xx 10^(23) xx 10^(23) c m ^(3)` Let `r` be the radius of the atom . Therefore. `(4)/(3) pi r ^(3) = (5)/(3) xx 10^(23) or r ~= 1.5 xx 10^(-10) m` |
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