1.

Given: Mass of electron =9.11xx10^(-31)kg Plank's constant =6.626xx10^(-34)Js The uncertaintly involved in the measurement of velocity with in a distance of 0.1Å is

Answer»

`5.79xx10^(7)MS^(-1)`
`5.79xx10^(8)ms^(-1)`
`5.79xx10^(5)ms^(-1)`
`5.79xx10^(6)ms^(-1)`

Solution :`DELTAX=0.1xx10^(-10)=10^(-11)m`
`Deltav=h/(4 pi m Deltax)`
`=(6.626xx10^(-34))/(4xx3.14xx9.11xx10^(-31)xx10^(-11))`
`=5.79xx10^(6)ms^(-1)`


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