1.

Given mass of the moon is 1/81 of the mass of the earth and corresponding radius is 1/4 of the earth. If escape velocity on the earth surface is 11.2 km / s , the value of same on the surface of the moon isA. `1.25km//s`B. `2.5m//s`C. `5m//s`D. `10m//s`

Answer» Correct Answer - B
`v_(e)=sqrt((2GM)/(R )),v_("e(moon)")=sqrt((2GM xx 4)/(81xx R))`
`= sqrt((4)/(81)((2GM)/(R )))=(2)/(9)xx v_(e )=2.5 m//s`


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