1.

Given n resistors each of resistance R, how will you combine them to get the (i) maximum(ii) minimum effective resistance ? What is the ratio of the maximum to minimum resistance ?

Answer»

Solution :(i)To GET the MAXIMUM effective resistance `R_(MAX)`, the RESISTANCES have to be joined in series. Then `R_(max) = nR `
(ii) For minimum resistance, the resistances have to be joined in parallel. Then, `R_("MIN") = R/n`
` therefore (R_(max))/(R_("min")) = (nR)/((R//n)) = n^2`


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