1.

Given,NH_(3(g))+3Cl_(2(g))iffNCl_(3(g))+3HCl_((g)),-DeltaH_(1)N_(2(g))+3H_(2(g))iff2NH_(3(g)),-DeltaH_(2)H_(2(g))+Cl_(2(g))iff2HCl_((g)),DeltaH_(3)The heat of formation of NCl_(3(g)) in the terms of DeltaH_(1), DeltaH_(2) and DeltaH_(3) is

Answer»

`DeltaH_(f)=-DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`
`DeltaH_(f)=DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`
`DeltaH_(f)=-DeltaH_(1)-(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`
NONE of these

Solution :Find `(1)/(2)N_(2)+(3)/(2)Cl_(2)rarrNCl_(3),DeltaH_(f)`
Multiply Eq. (ii) by 1/2 and add to Eq. (i), Eq. (III) by 3/2 and subtract from Eq. (i), we get
`DeltaH_(f)=-DeltaH_(l)-(DeltaH_(2))/(2)-[+(3)/(2)DeltaH_(3)]`
`=-DeltaH_(l)-(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`


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