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Given one test of differentiate [Co(NH_(3))_(5)Cl]SO_(4) and [Co(NH_(3))_(5)SO_(4)]Cl. |
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Answer» Solution :`(a) [Co(NH_(3))_(5)Cl]SO_(4) to [Co(NH_(3))_(5)Cl]^(+2)+SO_(4)^(2-)` `(b) [Co(NH_(3))_(5)SO_(4)]Cl to [Co(NH_(3))_(5)SO_(4)]^(-)+Cl^(-)` `(i)` Aqueous solution of `(a)` gives sulphate ion. When an addition of `BaCl_(2)` solution `(a)` gives WHITE precipitate of `BaSO_(4)` . But `(b)` does not give any precipitate. `(ii)` Aqueous solution of `(b)` gives chloride ion. When an addition of `AgNO_(3)` solution `(b)` gives curdy white precipitate of `AGCL`. But `(a)` does not give any precipitate. |
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