1.

Given, R=8.314JK^(-1)mol^-1), the work done during combustion of 0.090 kg of ethane (molar mass=30) at 300 K is

Answer»

`-18.7 kJ`
`18.7kJ`
`6.234kJ`
`-6.234kJ`

SOLUTION :Since, combustion TAKES place at constant pressure,
hence `DeltaH=nC_(p)dT`
`IMPLIES 3W=(0.090)/(30)XX(5)/(2)xx8.314xx300=18.7kJ`
`implies W=6.23kJ`


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