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Given : sin dita = p/q , find cos dita + sin dita in terms of p and q |
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Answer» sintheta = PERPENDICULAR/ hypotenuse= p/qlet perpendicular be pxlet hypotenuse be QX(qx)^2=(px)^2 + (X)^2THEN,base =√q^3-p^2xcos theta= base/ hypotenuse=q^3-p^2/qcos theta + SIN theta= √q^3-p^2/q + p/q= p+√q^2-p^2/p |
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