1.

Given that 2C(s) + 2O_(2)(g) rarr 2CO_(2)(g) Delta H = -787 kJ H_(2)(g) + (1)/(2)O_(2)(g) rarr H_(2)O(l) Delta H = -286 kJ C_(2)H_(2)(g) + (2) (1)/(2) O_(2)(g) rarr 2CO_(2)(g) + H_(2)O(l) Delta H = -1301 kJ Heat of formation of acetylene is :

Answer»

`-1802 kJ`
`+1786 kJ`
`-180.2 kJ`
`+228 kJ`

SOLUTION :RTHE required equation is
`2C + H_(2)(g) RARR C_(2)H_(2)(g)`
ADDING eqns. (i) and (ii) and substracting equation (iii)
`Delta H = 228 kJ`


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