Given that AM's are inserted between two sets of numbers a,2b and 2a,b where a,b E R suppose further that the mean between these sets of numbers is same then the ratio a: b =1) 1:n2) n: 13) n +1:14) n +2:n-1

Given that AM's are inserted between two sets of numbers a,2b and 2a,b

1.	Given that AM's are inserted between two sets of numbers a,2b and 2a,b where a,b E R suppose further that the mean between these sets of numbers is same then the ratio a: b =1) 1:n2) n: 13) n +1:14) n +2:n-1
Answer» Step-by-step explanation:a...n A.M.s........2B d= n+1 2b−a A m =a+m( n+1 2b−a )...(1) 2a.........n A.M's ...........b d= n+1 b−2a A m =2a+m( n+1 b−2a )...(2) equating (1) and (2) a= n+1 m (b+a)⇒ b a = n−m+1 m

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Given that AM's are inserted between two sets of numbers a,2b and 2a,b where a,b E R suppose further that the mean between these sets of numbers is same then the ratio a: b =1) 1:n2) n: 13) n +1:14) n +2:n-1​

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Given that AM's are inserted between two sets of numbers a,2b and 2a,b where a,b E R suppose further that the mean between these sets of numbers is same then the ratio a: b =1) 1:n2) n: 13) n +1:14) n +2:n-1