1.

Given that at 25^(@) C [Ag(NH_(3))_(2)]^(+) + e^(-) to Ag_(s) + 2NH_(3) ,E^(@) = 0.02 V and Ag^(+) + 1e^(-) to Ag(s) , E^(@) = 0.8 V Hence the order of magnitude of equilibrium constant of the reaction. [Ag(NH_(3))_(2)] to Ag^(+) + 2NH_(3) will be (antilog 0.22 = 1.66)

Answer»

`10^(-10)`
`10^(-6)`
`10^(-14)`
`10^(-18)`

Answer :C


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