1.

Given that C + O_(2) rarr CO_(2) Delta H^(theta) = -x kJ 2CO + O_(2) rarr 2CO_(2)Delta H^(theta) = - y kJ The enthalpy of formation of CO is :

Answer»

`(y - 2x)/(2)`
y - 2x
2x - y
`(X - y)/(2)`

Solution :`C + (1)/(2) O_(2) RARR CO`
:. `DELTA H(CO) = Eq. (i) - (1)/(2) Eq. (ii)`
`Delta H = - x + y//2 = (y - 2x)/(2)`


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