1.

Given that current through CA = 1A, current through C'A' = 2A/ Now if A is connected to A' and B is connected B'. Find currents through CA and C'A', respectively.

Answer»

`1 A, 3A`
`3A, 1A`
`1 A, 1A`
`3A, 3A`

Solution :d. `E_1 = (2+4) xx 1 = 6 V, E_2 = (2+4) xx 2 = 12 V`

There will be no current in AB and A'B', because all these
points are at the same potential. From D to A' :
`V_(D) + 6 - 2I_(1) = V_(A), but V_(D) = V_(A') = 0 `
`IMPLIES I_1 = 3A`
For outermost loop : `6-12 = 2I_1 + 4(I_1-I_2)or I_2 = 6A`
Current through C'A' = `I_1-I_2 = 3-6 = -3A`.


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