1.

Given that DeltaH_(f)(H)=218 kJ//mol,express theH-H bond energy in kcal/mol

Answer»

52.15
911
104
52153

Solution :`DeltaH_(f)(H)=218 KJ//mol`
`DeltaH_(f)(H_(2))=2xx218=436 kJ//mol`
1 kcal = 4.184 kJ
`436 kJ//mol = (1)/(4.184)xx436=104 kcal//mol`.


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