1.

Given that DeltaH_(f)(H)=218kJ//mol, express the H-H bond energy in kcal/mol

Answer»

52.15
911
104
52153

Solution :`(1)/(2)H_(2) to H,DELTAH,=218kJ//mol`
or `H_(2) to 2H,DeltaH,=436kJ//mol`
`=(436)/(4.18)=104.3kcal//mol`
thus, 104.3 kcal/mol energy is absorbed for breaking of one mole of H-H BONDS. Hence, H-H bond energy is 104.3 kcal/mol.


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