Given that density of water is "1 g mL"^(-1). What is its density in k – InterviewSolution

1.	Given that density of water is "1 g mL"^(-1). What is its density in kg m^(-3)?
Answer» Solution :`"1 G mL"^(-1)="1 g cm"^(-3)=(1g)/(1CM^(3))=1gxx(1kg)/(1000g)XX(1)/(cm^(3))xx(100CM)/(1m)xx(100cm)/(1m)xx(100cm)/(1m)=1000kgm^(-3)`

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