Given that `E_(Fe^(2+)//Fe)^(.)=-0.44V,E_(Fe^(3+)//Fe^(2+))^(@)=0.77V` if `Fe^(2+),Fe^(3+)` and `Fe` solid are kept together thenA. `Fe^(3+)` IncreaseB. `Fe^(3+)` decreaseC. `Fe^(2+)//Fe^(3+)` remains unchangedD. `Fe^(2+)` decreases

Given that `E_(Fe^(2+)//Fe)^(.)=-0.44V,E_(Fe^(3+)//Fe^(2+))^(@)=0.77V`

1.	Given that `E_(Fe^(2+)//Fe)^(.)=-0.44V,E_(Fe^(3+)//Fe^(2+))^(@)=0.77V` if `Fe^(2+),Fe^(3+)` and `Fe` solid are kept together thenA. `Fe^(3+)` IncreaseB. `Fe^(3+)` decreaseC. `Fe^(2+)//Fe^(3+)` remains unchangedD. `Fe^(2+)` decreases
Answer» Correct Answer - B `{:("Anode",,Ferarr Fe^(@+)+2e^(-),,),("Cathode",,[Fe^(3+)+e^(-)rarrFe^(2+)]xx2,,),("Cell",,Fe+2Fe^(3+)rarr3Fe^(2+),,),(E^(2)=0.77-(-0.44)=1.21V,,,,):}` `DeltaG^(@)=( - )ve" "` Reaction is spontaneous.

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Given that `E_(Fe^(2+)//Fe)^(.)=-0.44V,E_(Fe^(3+)//Fe^(2+))^(@)=0.77V` if `Fe^(2+),Fe^(3+)` and `Fe` solid are kept together thenA. `Fe^(3+)` IncreaseB. `Fe^(3+)` decreaseC. `Fe^(2+)//Fe^(3+)` remains unchangedD. `Fe^(2+)` decreases

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