1.

Given that E^(@)(Zn) = -0.76V and E^(@)(Cu) = 0.34V. Calculate the emf of the cell with cell reaction

Answer»

`-42 V`
`1.42 V`
`-1.10 V`
`+1.10 V`

Solution :`E_("cell")^(0)=UNDERSET((Cu))(E_(R)^(0))-underset((Zn))(E_(R)^(0))=0.34-(-0.76)=1.1V`


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