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Given that Fe^(3+)+e leftrightarrow Fe^(2+), E^@=0.77V Fe^(2+)+2e leftrightarrow Fe, E^@=-0.44V What will be the E^@ value for the following half cell. Fe^(3+)+ 3e leftrightarrow Fe |
| Answer» SOLUTION :`-0.04V` | |