1.

Given that for a reaction of nth order the integrated rate equation is K=1/(t(n-1))[1/(C^(n-1))-1/(C_(0)^(n-1))] where Cand C_(0) are the concentration of reactant at time to initiallyh respectivley. The t_(3//4) and t_(1//2) are related as (t_(3//4) is time required to C to become C/4)

Answer»

`t_(3//4)=t_(1//2)[2^(n-1)+1]`
`t_(3//4)=t_(1//2)[2^(n-1)-1]`
`t_(3//4)=t_(1//2)[2^(n+1)+1]`
`t_(3//4)=t_(1//2)[2^(n+1)-1]`

SOLUTION :`(((t_(3))/4))/(((t_(1))/2))=[2^((n-1))+1]`


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