1.

Given that for a reaction of nth order, the integrated rate equation is: K=1/(t(n-1))[1/C^(n-1)-1/C_(0)^(n-1)], where C and C_(0) are the concentration of reactant at time t and initially respectively. The t_(3//4) and t_(1//2) are related as t_(3//4) is time required for C to become C_(1//4) :

Answer»

`t_((3)/(4))=t_((1)/(2))][2^(n-1)+1]`
`t_((3)/(4))=t_((1)/(2))[2^(n-1)-1]`
`t_((3)/(4))=t_((1)/(2)[2^(n+1)-1]`
`t_((3)/(4))=t_((1)/(2))[2^(n+1)+1]`

ANSWER :A


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