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Given that (i) `O(g) + e^(-) rarr O^(-)(g) ,DeltaH= -142kJ mol^(-1)` (ii) `O(g) + 2e^(-)rarr O^(-2) (g), DeltaH = + 712 kJ mol^(-1)` Calculate `DeltaH` for the reaction `O^(-)(g) +e^(-) rarr O^(-2) (g)`.

Answer» Eqn. (ii) - Eqn. (i) gives `O^(-)(g) + e^(-) rarr O^(2-) (g), Delta H =712 -( - 142) kJ mol^(-1) = 854 kJ mol^(-1)`


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