1.

Given that O(g) + e^(-) rarr O^(-)(g) Delta H = - 142 kJ mol^(-1) O(g) + 2e^(-) rarr O^(2-)(g) DeltaH =+712kJmol^(-1) The heat change for the reaction O^(-)(g) + e^(-) rarr O^(2-)(g) is :

Answer»

`- 570 KJ`
570 kJ
`+ 854 kJ`
`- 854 kJ`

Solution :(i) `O(g) + e^(-) RARR O^(-) Delta H = - 142 kJ`
(ii) `O(g) + 2e^(-) rarr O^(2-) Delta H = 712 kJ`
Subtract eq. (i) from eq.(ii).
`O(g) + e^(-) rarr O^(2-) Delta H = 854 kJ`


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