1.

Given that the abundances of isotopes .^(54)Fe, .^(56)Fe and .^(57)Fe are 5%, 90% and 5% respectively, the atomic mass of Fe is

Answer»

55.85
55.95
55.75
56.05

Solution :`.^(54)Fe rarr 5%`
`.^(56)Fe rarr 90%`
`.^(57)Fe rarr 5%`
Av. Atomic mass `= x_(1) A_(1) + x_(2) A_(2) + x_(3) A_(3)`
`= 54 XX 0.05 + 56 xx 0.9 + 57 xx 0.05 = 55.95`


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