1.

Given that the abundances of isotopes .^(54)Fe,.^(56)Fe and .^(57)Fe are 5%,90% and 5% respectively, the atomic mass of Fe is:

Answer»

55.85u
55.95u
55.75u
56.05u

Solution :ATOMIC MASS of `FE=(5)/(100)xx54+(90)/(100)xx56+(5)/(100)xx57`
=55.95amu


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