1.

Given that the abundances of isotopes ""^54 Fe, ""^56Fe and ""^57Feare 5%, 90% and 5% respectively, the atomic mass of Fe is

Answer»

55.85
55.95
55.75
56.05

Solution :Atomic MASS of Fe
`= (5 xx 54 +90 xx 56 + 5 xx 57)/(100)`
` = (270 + 5040 + 285)/(100)`
= 55.95


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