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InterviewSolution
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Given that the angle of minimum deviation for a colour is 43^(@)48' and its RI = 1.588, Calculate refracting angle of the prism. |
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Answer» SOLUTION :`D=43^(@)48., n=1.588` `n=(SIN((A+D)//2))/(sinA//2)` `=(sin(A//2+(43^(@)48.)//2))/(sinA//2)` `=(sin(A//2 +21^(@)54.))/(sinA//2)` `1.588=(siniA//2cos21^(@)54.+sin21^(@)54.cosA//2)/(sinA//2)` `1.588=cos21^(@)54.+sin21^(@)54.+sin21^(@)54. (1)/(tanA//2)` `=0.9278+0.3730+(1)/(tanA//2)` `0.6602=0.3730xx(1)/(tanA//2)` `tanA//2=0.5649` `A//2=29^(@)28.` `therefore A=58^(@)56.` |
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