Given that the dissociation constant for H_(2)O is K_(w) = 1 xx 10^(-1 – InterviewSolution

1.	Given that the dissociation constant for H_(2)O is K_(w) = 1 xx 10^(-14) "mole"^(2)//"litre"^(2). What is the pH of a 0.001 molar KOH solution
Answer» `10^(-11)` `10^(-3)` 3 11 Solution :PH = 14 - POH = 14 - 3 = 11.

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