Given that the equation of motion of a mass is `x = 0.20 sin (3,0 t) m` . Find the velocity and acceleration of the mass when the object is `5 cm` from its equilibrium position. Repeat for `x = 0`.

Given that the equation of motion of a mass is `x = 0.20 sin (3,0 t) m

1.	Given that the equation of motion of a mass is `x = 0.20 sin (3,0 t) m` . Find the velocity and acceleration of the mass when the object is `5 cm` from its equilibrium position. Repeat for `x = 0`.
Answer» Correct Answer - B::D `omega = 3rad//s` `A = 0.2m` At `x = 5cm` `v = +-omegasqrt(A^(2) - x^(2))` `= +- 3.0sqrt((0.2)^(2) - (0.05)^(2))` `= +- 0.58m//s` `a = - omega^(2)x = - (3)^(2)(0.05)` ` = - 0.45m//s` At `x = 0` `v = +-omega A` `= +- (3.0)(0.2)` `= +- 0.6 m//s` `a = - omega^(2)x = - (3)^(2)(0)` `= 0`

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Given that the equation of motion of a mass is `x = 0.20 sin (3,0 t) m` . Find the velocity and acceleration of the mass when the object is `5 cm` from its equilibrium position. Repeat for `x = 0`.

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