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Given that the mass of a molecule of hydrogen is 3.34xx10^(-27) kg. Calculate Avogadro's number. |
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Answer» Solution :MASS of one molecule of `H_(2)=3.34xx10^(-27)` kg Molecular mass of HYDROGEN `=2xx10^(-3)` kg The Avogadro's NUMBER `N_(A)`, which is the number of molecules in one gram molecule of hydrogen is given by `N_(A)=(2xx10^(-3))/(3.34xx10^(-27))=5.988xx10^(23)` molecules. |
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