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Given that the position of the body in `m` is a function of time as follows : `x = 2t^(4) + 5t + 4` The mass of the body is `2 kg` . What is the increase in its kinetic energy onesecond after the stert of motion?A. `168 J`B. `169 J`C. `32 J`D. `144 J` |
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Answer» `x = 2t ^(4) + 5t + 4 implies v = (dx)/(dt) = 8 t + 5` at `t = 0, v = 5 m//s` at` t = 1 s`, `v = 8 xx 1 + 5 = 13 m//s` Increases in `KE = (1)/(2) m[13^(2) - 5^(2)] = 144 J` |
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