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| 1. |
Given that the standard electrode potential (E^(@)) of metals are: K^(+)//K=-2.93V,Ag^(+)//Ag=0.80V,""Cu^(2+)//Cu=0.34V,Mg^(2+)//Mg=-2.37V, Cr^(3+)//Cr=-0.74V,Fe^(2+)//Fe=-0.44V Arrange these metals in an increasing order of their reducing power. |
| Answer» SOLUTION :Higher the oxidation POTENTIAL more easily it is oxidised and HENCE stronger is the reducing power. Therefore order is `Ag lt CU lt Fe lt Mg lt K`. | |