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Given that the standard electrode potentials (E^(@)) of metals are: K^(+)//K = -2.93 V, Ag^(+)//Ag = 0.80 V, Cu^(2+)//Cu = 0.34 V, Mg^(2+)//Mg = -2.37 V, Cr^(3+)//Cr = -0.74 V, Fe^(2+)//Fe = -0.44 V. Arrange these metals in an increasing order of their reducing power. |
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Answer» Solution :Greater the NEGATIVE value of the standard ELECTRODE potential `(E^(@))`, greater is the reducing power of the electrode. The INCREASING order of reducing power is: `AG^(+)//Ag lt CU^(2+)//Cu lt Fe^(2+) //Fe lt Cr^(3+)//Cr lt Mg^(2+) //Mg lt K^(+)//K` |
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