InterviewSolution
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InterviewSolution
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Given that x, `y in R`. Solve: `x/(1+2i)+y/(3+2i)=(5+6i)/(8i-1)` |
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Answer» `(x)/(1+2i)+(y)/(3+2i)=(5+6i)/(8i-1)` or `(x (1-2i))/(1-4i^(2))+(y(3-2i))/(9-4i^(2)) = ((5+6i)(8i+1))/((8i)^(2)-1^(2))` `or (x-2x i)/(5) +(15y -10yi)/(13)+(40 i + 5- 48+6i)/(-64-1)` `or (13x -26x i+15y - 10yi)/(65) = (-43 + 46i)/(-65)` or (13x+ 15y) -i(26x+ 10y)= 43-46i` Equating real and imaginary parts, we get `13x + 15y = 43 " "(1)` `13x + 5y = 23" "(2)` Solving for x and y we, get x = 1 and y =2 |
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