Given the bond energies of `H - H` and `Cl - Cl` are `430 kJ mol^(-1)` and `240 kJ mol^(-1)`, respectively, and `Delta_(f) H^(@)` for `HCl` is `- 90 kJ mol^(-1)`. Bond enthalpy of `HCl` isA. 290 `KJ "mol"^(-1)`B. `380 KJ "mol"^(-1)`C. `425 KJ "mol"^(-1)`D. `245 KJ "mol"^(-1)`

Given the bond energies of `H - H` and `Cl - Cl` are `430 kJ mol^(-1)`

1.	Given the bond energies of `H - H` and `Cl - Cl` are `430 kJ mol^(-1)` and `240 kJ mol^(-1)`, respectively, and `Delta_(f) H^(@)` for `HCl` is `- 90 kJ mol^(-1)`. Bond enthalpy of `HCl` isA. 290 `KJ "mol"^(-1)`B. `380 KJ "mol"^(-1)`C. `425 KJ "mol"^(-1)`D. `245 KJ "mol"^(-1)`
Answer» Correct Answer - B `DeltaH_("reaction")=Delta_(H-H) + DeltaH_(Cl-Cl)-2DeltaH_(HCl)` or `DeltaH_(Cl-Cl) =(430+ 240 -(-90))/(2)` `=(760)/(2)=380 KJ "mol"^(-1)`

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Given the bond energies of `H - H` and `Cl - Cl` are `430 kJ mol^(-1)` and `240 kJ mol^(-1)`, respectively, and `Delta_(f) H^(@)` for `HCl` is `- 90 kJ mol^(-1)`. Bond enthalpy of `HCl` isA. 290 `KJ "mol"^(-1)`B. `380 KJ "mol"^(-1)`C. `425 KJ "mol"^(-1)`D. `245 KJ "mol"^(-1)`

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