1.

Given the data at 25^(@)C. Ag+I^(-) to Agl+e^(-) , E^(@)=-0.152" V " Ag to Ag^(+)+e^(-) , E^(@)=-0.800" V ". The value of log K_(sp) for AgI is :

Answer»

-8.12
8.612
-37.83
-16.13

Solution :(d) `Agl+e^(-) to AG+I^(-) , E^(@)=-0.152" V "`
`Ag to Ag^(+)+e^(-) , E^(@)=-0.800" V "`
`Agl to Ag^(+)+I^(-) , E^(@)=-0.952" V "`
`E_(cell)^(@)=(0.059)/(N)logK=(0.059)/(n)logK_(SP)`
`logK_(sp)=(E_(cell)^(@)xxn)/(0.059)=((-0.952)XX1)/((0.059))=-16.135`


Discussion

No Comment Found

Related InterviewSolutions