1.

Given the displacement of the body as x = (2t^4 + 5)m and mass is 2 kg. What is the increase in K.E. in one second :

Answer»

8 J
16 J
32 J
64 J

Solution :Given `x=2r^(4)+5:.(dx)/(DT)=8r^(3)implies v=8t^(3)`
`:.` Velocity after 1 second = 8m/s.
Now `K.E."1/2mv^(2)=1/2xx2xx(8)^(2)=64 J`


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