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Given the enthalpy of formation of `CO_(2)(g)` is -94.0 KJ, of CaO(s) is -152 KJ, and the enthalpy of the reaction `CaCO_(3)(s) rarr CaO(s)+CO_(2)(g)` is 42KJ, the enthalpy of formation of `CaCO_(3) (s)` isA. `-42` KJB. `-202` KJC. `+202` KJD. `-288` KJ |
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Answer» Correct Answer - D `CaCO_(3(s))rarr CaO_((s))+CO_(2(g)) , Delta H=42 kJ` `Delta H=Sigma (Delta E_(f))_(P)-Sigma (Delta E_(f))_(R )` `42=[-152)+(-94)]-Delta H_(f)(CaCO_(3))` `therefore H_(f)(CaCO_(3))=-246-42 =-288 kJ` |
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