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    				| 1. | Given the equation `4x^2+2sqrt(3)x y+2y^2=1`. Through what angle should the axes be rotated sothat the term `x y`is removedfrom the transformed equation. | 
| Answer» Correct Answer - `pi//6,2pi//3` Comparing the given equation with `ax^2+2hxy+by^2` we get `a=4,h=sqrt3,b=2`. Let `theta` be the angle through which the axes are to be rotated. Then, `tan 2theta=(2h)/(a b)` or `tan2theta=(2sqrt3)/(4-2)=sqrt(3)=tan.(pi)/(3)` or `2theta=(pi)/(3),pi+(pi)/(3)` or `theta=(pi)/(6),(2pi)/(3)` | |