InterviewSolution
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InterviewSolution
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Given the equilibrium constants `HgCl^(o+)+Cl^(ɵ) rarr HgCl_(2), K_(1)=3xx10^(6)` `HgCl_(2)+Cl^(ɵ) rarr HgCl_(3)^(ɵ), K_(2)=8.9` The equilibrium constant for the disproportionation equilibrium `2HgCl_(2) rarr HgCl^(o+)+HgCl_(3)^(ɵ)` isA. `-3.3xx10^(5)`B. `3xx10^(-5)`C. `3.3xx10^(5)`D. `3xx10^(-6)` |
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Answer» Correct Answer - D a. `HgCl^(o+)+Cl^(ɵ) rarr HgCl_(2) … K_(1)` b. `HgCl_(2)+Cl^(ɵ) rarr HgCl_(3) …K_(2)` The eq. constant (k) for the reaction, `2HgCl_(2) rarr HgCl^(o+)+HgCl_(3)^(ɵ)` Can be obtained by reversing equation (a) and adding to equation (b). `K=1/K_(1)xxK_(2)=K_(2)/K_(1)=8.9/(3xx10^(6))~~3xx10^(-6)` |
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