Given the following data : Determine at what temperature the following reaction is spontanous? `FeO(s)+C_("graphite")toFe(s)+CO(g)`A. 298 KB. 668 KC. 966KD. `DeltaG^(@)` is +ve, hence the reaction will never be spontaneous.

Given the following data : Determine at what temperature the followin

1.	Given the following data : Determine at what temperature the following reaction is spontanous? `FeO(s)+C_("graphite")toFe(s)+CO(g)`A. 298 KB. 668 KC. 966KD. `DeltaG^(@)` is +ve, hence the reaction will never be spontaneous.
Answer» Correct Answer - C `DeltaH_("reaction")=sum{DeltaH_(f" "Fe(s))^(@)+DeltaH_(f" "CO" "(g))^(@)}-{DeltaH_(f" "FeO(s))^(@)+DeltaH_(f" "C("graphite"))^(@)}` `=(0-110.5)-(-266.3+0)=155.8kJ" "mol^(-1)` `DeltaS_("reaction")=sum[S_(Fe(s))^(@)+S_(Co(g))^(@)]-[S_(FeO(s))^(@)+S_(C("graphite"))^(@)]` `=(27.28+197.6)-(57.49+5.74)` `=161.65JK^(-1)" "mol^(-1)` For spontaneous reaction, `T gt (DeltaH)/(DeltaS),T gt (155.8xx1000)/(161.65)` `thereforeT gt 966K`

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Given the following data : Determine at what temperature the following reaction is spontanous? `FeO(s)+C_("graphite")toFe(s)+CO(g)`A. 298 KB. 668 KC. 966KD. `DeltaG^(@)` is +ve, hence the reaction will never be spontaneous.

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