1.

Given the following entropy values ( in JK^(-1) "mol"^(-1)) at 298 K and 1 atm: H_(2)(g):130.6, Cl_(2)(g):223.0, HCl(g): 186.7. The entropy change (in JK^(-1) "mol"^(-1)) for the reaction H_(2)(g) + Cl_(2)(g) to 2HCl(g) , is

Answer»

`+540.3`
`+727.0`
`-166.9`
`+19.8`

SOLUTION :`H_(2)(G) + Cl_(2)(g) to 2HCl(g) `
`Delta_(I)S=sumS_(m)""^(@)(P) -sumS_(m)""^(@)(R)`
`Delta_(I)S^(@)=2xxS_(m)^(@)(HCL) - [S_(m)^(@)(Cl_(2)) + S_(m)^(@) (H_(2))]`
`=(2xx186.7)-(223+ 130.6)`
`=373.4-353.6`
`=+19.8 JK^(-) "mol"^(-)`


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