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Given the linear equation x+2y+1=0x+2y+1=0, if another pair formed is 2x+4y−3=02x+4y−3=0.then solution of the equations is |
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Answer» 2x+y=6 ⟹y=6−2x Let, x=1, then y=6−2(1)=4 Similarly, when x=2,y=2 x−2y+2=0 ⟹x=2y−2 Let, y=0, then x=2(0)−2=−2 Similarly, when y=2,x=2 PLOTTING the above points on the graph, we GET, the vertices of the traingle, i.e. A(2,3),B(3,0),C(−2,0) ∴ AREA of the triangle = 2 1 ×5units×2units =5 SQ. unitsStep-by-step explanation: |
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